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Java · DSA · Hashing ◐ Find the element with the second-highest frequency by counting every value once in a hash[] array, then scanning it with two leader slots. Watch it run step by step on your own input. 01 Problem 02 Code 03 Tracer 04 Complexity 05 Revision 06 Quiz 01 The problem Given an array of N non-negative integers, print the element that occurs the second most times. Rank values by frequency. On a tie, the value that appears first in the array ranks higher. If there is only one distinct value, print -1 . For [1, 2, 2, 3, 3, 3] , the frequencies are 1 → 1, 2 → 2 and 3 → 3. Value 3 is first, so the answer is 2 . Type an array to see what the code prints and how often each value occurs. Array (spaces or commas) Run 02 The hashing code This is a faster alternative to the brute-force version. It avoids recounting each value with...